80x^2=80

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Solution for 80x^2=80 equation:



80x^2=80
We move all terms to the left:
80x^2-(80)=0
a = 80; b = 0; c = -80;
Δ = b2-4ac
Δ = 02-4·80·(-80)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*80}=\frac{-160}{160} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*80}=\frac{160}{160} =1 $

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